يظهر لي الخطأ Notice: Undefined variable في PHP

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  message:

Notice: Undefined variable: pass2 in D:\xampp\htdocs\server\phping\fo2\1.php on line 7

   html :

<form class="formHide" action="1.php" method="post">

  <div id="creating" class="creating_hide">

    <h4>Create A New Account</h4>

    <input id="create_email" type="email" name="create_email" placeholder="   Email....  " required/>

    <br>

    <input id="password_email" type="password" name="create1_pass" placeholder="   Password....  " required/>

    <br>

    <input id="password2_email" type="password" name="passed" placeholder="   Password(again)....  " required/>

    <br>

    <button id="create2" name="create2"> Create</button>


  </div>

</form>

php :

<?php

$database = new PDO("mysql:host=localhost;dbname=users;",$username,$password);


if(isset($_POST['create2'])){

  if($password === $pass2){


    echo 'done';      

    $pass2 = $_POST['create1_pass'];

    $email = $_POST['create_email'];

    $password = $_POST['create1_pass'];

    $addData = $database->prepare(" INSERT INTO costom(Emails,Passwords) VALUES('$email','$password')");

    $addData->execute();

  }else{

    echo 'not the same password! try again';         

  }

}