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اقتباس

 

اقتباس

اقتباس

You have an array on N size with random numbers. Write a multithreaded program that performs the following operations on this array:

Thread 1 sorts the even numbers

Thread 2 sorts the odd numbers

Thread 3 merg the results (even number in the top part of the array).

مطلوب هاد السؤال مني حليت Thread1 و Thread 2,هلا Thread 3 كيف بتنحل علما انو الدكتور طالب انو ما لازم تشتغل الا بعد ما Thread1وThread 2يشتغلوا مع بعض ويخلصوا

import java.util.Scanner;

public class main 
{
	public static void main(String[] args)
	{
	    
	    	int length = 0;
	    Scanner sc=new Scanner(System.in);
	    System.out.print("Length of array:");
	    length=sc.nextInt();
	    int[] array = new int[length];
	    System.out.println("Enter number of array: ");
	 
	    for(int i=0; i<length; i++)
	    {
	        array[i]=sc.nextInt();
	    }
	    
	    
		  

	    ThreadSortEven runnablee=new ThreadSortEven();   
	    runnablee.setArray(array,length);
	    Thread thread1 =new Thread(runnablee);    
	    thread1.start();
	    		  

	    ThreadSortOdd runnable=new ThreadSortOdd();   
	    runnable.setArray(array,length);
	    Thread thread2 =new Thread(runnable);    
	    thread2.start();

	}
}


class ThreadSortEven implements Runnable  {


    int[] array;
    int length;


   public void setArray(int[] array,int length){
       this.array=array;
       this.length=length;
   }


	public void run() {
	
		    System.out.println("-------------------");
		    System.out.println("sorted even array :");
		
		for(int i=0; i<length; i++)
        {
			if (array[i]%2==0) 
			{
			  

		          System.out.println(array[i]);
        	}
        }	
	}
	

}




class ThreadSortOdd implements Runnable  {


    int[] array;
    int length;


   public void setArray(int[] array,int length){
       this.array=array;
       this.length=length;
   }


	public void run() {
	
		    System.out.println("-------------------");
		    System.out.println("sorted odd array :");
		
		for(int i=0; i<length; i++)
        {
			if (array[i]%2!=0) 
			{
			 
		          System.out.println(array[i]);
        	}
        }	
	}
	

}